Rectilinear Motion Problems And | Solutions Mathalino Upd

v(4) = 4(4) - (64)/3 + 3 = 16 - 21.333 + 3 = -2.333 m/s (moving negative direction).

A particle moves with position ( s(t) = 2\sin(3t) ), ( t ) in seconds, ( s ) in meters. Find: rectilinear motion problems and solutions mathalino upd

16 t sub 1 squared plus open bracket 248 open paren t sub 1 minus 2 close paren minus 16 open paren t sub 1 minus 2 close paren squared close bracket equals 1000 Solving this yields They pass at (or approx. 600 ft) above the ground 3. Constant Deceleration (The Train Problem) v(4) = 4(4) - (64)/3 + 3 = 16 - 21

He passed.